this assumes two domains, right? IIRC, every discussion of twinning i have read treats the problem in terms of two domains. what is the basis for only having two domains (besides simplicity)?
The twin law is a rotation operator. the order of that rotation (2fold, 3 fold, 4 fold, 6fold) determines the number of domains for a single twin law.
someone mentioned a three-domain twinning problem (maybe ccp4 or phenix bb, last week or so) - wouldn't that need "1-alpha-(third domain fraction)"?
yes! P
-bryan
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